In Tom's modified booth algorithm (which is simpler and different from the real modified both algorithm), we want to multiply the following two 4-bit numbers that we will assume to be positive; that is, not 2's complement form, for example, 1111 = 15 not -1. (you can just pretend that each number has a leading zero if you prefer) 0101 multiplicand x 1011 multiplier recall that in Tom's modified booth that we will do this multiplication by adding only two numbers instead of four and that the values we need are Ox, 1x, 2x, and 3x the multiplicand shifted into their appropriate positions (we are encoding the multiplier 2 bits at a time). This allows us to double the speed of the multiplication! With all that in mind, what two numbers will we add to get the final result. Express each without any extra leading zeroes; for example, 3 is 11 not 011. Give the smaller one first then the larger one. smaller: larger: What is the final result of the multiplication?

Word vocabulary words: print, proofread, status line, graphics, font effects, left margin, justification, line spacing, copy/paste, data. review words: font point, bold, save, center, error. fill in the correct word for the definition and then transfer the letters to the appropriate spot by number. some numbers will be found multiple times. you will end up with a quotation about…… what else? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 k 16 17 18 19 20 21 22 23 24 25 8 27 28 29 w 31 32 k 34 35 36 w h 39 40 41 42 8 44 45 46 47 48 49 50 51 52 53 54 55 .1. a software function that records keystrokes on a disk or drive so information can be 5 4 52 9 later retrieved. p n 2. to produce a paper copy of information. 10 7 12u n 3. a display that shows the location of the cursor, pages, etc. 45 46 18 27 36 20 42p4. pictures or images, located in clip art or other files. 6 24 44 28 34 49 555. any mis-stroke of a key. 47 41 48 2 10 n6. allows major changes to the font such as shadow, emboss, etc. 21 25 46 35 23 21 29 14 22 17 n7. a feature that centers lines of text horizontally. 49 53 46 9 51 p8. size of the font 31 16 22 b l 9. a feature that prints designated text darker than the rest to add emphasis. 32 3 . p10. to compare copy on a display screen or printout to the original 24 39 25 23 54 9 50 3 and correct errors. j un 11. a feature that allows text to be aligned at the left 11 12 7 21 16 49 40 46 34 2 and right margins. leftn 12. amount of blank space on the left side of the paper. 8 18 41 6 34 linen 13. number of blank lines between lines of text. 17 4 49 13 1914. any information inputted into the computer. 3 4 46 44 p /p15. feature that duplicates text from one location and places it in another.

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

Writing a modular program in visual c++. i am new to this and not sure what i am missing. i am getting the following error: baddate.cpp: in function ‘int main()’: baddate.cpp: 50: 3: error: ‘else’ without a previous ‘if’elsehere are the instructions and code: writing a modular program in c++in this lab, you add the input and output statements to a partially completed c++ program. when completed, the user should be able to enter a year, a month, and a day. the program then determines if the date is valid. valid years are those that are greater than 0, valid months include the values 1 through 12, and valid days include the values 1 through 31.notice that variables have been declared for you.write the simulated housekeeping() function that contains the prompts and input statements to retrieve a year, a month, and a day from the user.include the output statements in the simulated endofjob() function. the format of the output is as follows: month/day/year is a valid date.ormonth/day/year is an invalid date.execute the program entering the following date: month = 5, day = 32, year = 2014. record the output of this program.execute the program entering the following date: month = 9, day = 21, year = 2002. record the output of this /* program name: baddate.cppfunction: this program determines if a date entered by the user is valid.input: interactiveoutput: valid date is printed or user is alerted that an invalid date was entered*/#include bool validatedate(int, int, int); using namespace std; int main(){// declare variablesint year; int month; int day; const int min_year = 0, min_month = 1, max_month = 12, min_day = 1, max_day = 31; bool validdate = true; // this is the work of the housekeeping() method// get the year, then the month, then the daycout< < "enter the year"< > year; cout< < "enter the month"< > month; cout< < "enter the day"< > day; // this is the work of the detailloop() method// check to be sure date is validif(year < = min_year) // invalid yearvaliddate = false; else if (month < min_month || month > max_month) // invalid monthvaliddate = false; else if (day < min_day || day > max_day) // invalid dayvaliddate = false; // this is the work of the endofjob() method// test to see if date is valid and output date and whether it is valid or notif(validdate == true); {// output statementcout<