Computers and Technology, 21.05.2021 09:00 VeIocity
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Computers and Technology, 21.06.2019 23:00
Fast sportcars the top speeds of sportscars, given in miles per hour, are: 155 mph bmw m5 217 mph lamborghini aventador spyder 205 mph ferrari 488 205 mph nissan gtr 197 mph chevrolet corvette stingray zr1 258 mph bugatti veyron supersport 195 mph dodge viper 270 mph hennessey venom 155 mph bmw m3 195 mph mercedes sl given: topspeeds=[155; 217; 205; 205; 197; 258; 195; 270; 155; 195]; carnames=string(["bmw m5" "lamborghini aventador spyder" "ferrari 488" "nissan gtr" "chevrolet corvette stingray zr1" "bugatti veyron supersport" "dodge viper" "hennessey venom" "bmw m3" "mercedes sl"]); the variable is a rectangular array. write a function called selectcars to identify cars with the top speed within a given range, and display the identified names. the selected cars speed will be in a range given by lowerbound < speed < upperbound. inputs to the function selectcars are: a column array os all car top speeds named topspeeds, the corresponding chara
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Computers and Technology, 22.06.2019 09:50
Assume that you have an sorted array of records. assume that the length of the array (n) is known. give two different methods to search for a specific value in this array. you can use english or pseudo-code for your algorithm. what is the time complexity for each algorithm and why?
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Computers and Technology, 23.06.2019 03:10
Acomputer has a two-level cache. suppose that 60% of the memory references hit on the first level cache, 35% hit on the second level, and 5% miss. the access times are 5 nsec, 15 nsec, and 60 nsec, respectively, where the times for the level 2 cache and memory start counting at the moment it is known that they are needed (e.g., a level 2 cache access does not even start until the level 1 cache miss occurs). what is the average access time?
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Computers and Technology, 23.06.2019 06:30
Who can provide you with a new password when you have forgotten your old one? your provide you with a new password in case you forget your old one.
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