In the code snippet below, pick which instructions will have pipeline bubbles between them due to hazards. a. lw $t5, 0($t0)
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
d. sw $t3, 12($t0)
e. lw $t2, 8($t0)
f. add $t1, $t5, $t2
g. sw $t1, 16($t0)

b. lw $t4, 4($t0)

c. add $t3, $t5, $t4

Explanation:

Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.

a.clothing is the correct answer

uiy

explanation: