g 4-6 you've been given the network 200.5.0.0 /24 and need to subnet it using vlsm as follows: bldg 1 30 hosts bldg 2 10 hosts bldg 3 10 hosts bldg 4 4 hosts what will be the network address for bldg 3

The answer is  "200.5.0.0 32/28".

Explanation:

The requirement of the Bldg is =30.

The number of the host bits which is needed = 5

Therefore the subnet mask will be =/27

for bldg 3 netmask could be= /28

and when the /28 after that the last octet will be= 00100000.

00100000 converting value into a decimal value that is = 32.

therefore the correct value is 200.5.0.32 /28.

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