For any element in keyslist with a value greater than 100, print the corresponding value in items list, followed by a space. ex: if keyslist = {42, 105, 101, 100} and items list = {10, 20, 30, 40}, print: 20 30 since keyslist[1] and keyslist[2] have values greater than 100, the value of itemslist[1] and itemslist[2] are printed.

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

To produce a starlight effect in her photograph, lina should choose the filter for her camera.

20 points archie wants to use a reflector as he photographs a newlywed couple. what would he consider in his choice? a. shadow and sunny b. homemade and professional c. lamps and boards d. incident and reflected e. neutral density and enhancement