A location in memory which stores a value, the value can change as the program is running is known as a

Your program will make use of long long int variables for all calculations. note: the use of long long int requires that you have c++11 support. you should have this automatically if you are using a newer version of visual studio. the support is there for gcc as well, but you may need the -std=c++11 or -std=c++0x compiler flag. you first need to read in the total number of seconds. there is no prompt for the read (that is, you just do the cin without using a cout to display a prompt). this is going to seem a little strange when you are running your program in your ide

What is the worst-case complexity of the maxrepeats function? assume that the longest string in the names array is at most 25 characters wide (i.e., string comparison can be treated as o( class namecounter { private: int* counts; int nc; string* names; int nn; public: namecounter (int ncounts, int nnames); int maxrepeats() const; }; int namecounter: : maxrepeats () { int maxcount = 0; for (int i = 0; i < nc; ++i) { int count = 1; for (int j = i+1; j < nc; ++j) { if (names[i] == names[j]) ++count; } maxcount = max(count, maxcount); } return maxcount; }

What is the total resistance in a circuit that contains three 60 ohm resistors connected in a series? a. 20 ohms b. 120 ohms c. 60 ohms d. 180 ohms