Suppose we are given an array A that contains n distinct integers. Our goal is to find a "nice" pivot A[m] that has the following property: A[m] lies between the (n/10)-th smallest and the (n/10)-th largest element of A. You have access to a quantum oracle Q that works as follows: Q(A0 ) returns the median of an array A0 in constant time whenever A0 has at most n 1/3 elements. Q does not work when the input array has more than n 1/3 elements. Design and describe an efficient algorithm that returns a nice pivot of A by using the quantum oracle Q. Analyze the running time and argue the correctness of your algorithm. You can assume that it only takes constant time to submit subarray A[i..j] of A to the quantum orcale Q. Creating an array of size k takes Θ(k) time.‘

Sally is editing her science report about living things. she needs to copy a paragraph from her original report. order the steps sally needs to do to copy the text to her new document.

Select the correct answer. which step can possibly increase the severity of an incident? a. separating sensitive data from non-sensitive data b. immediately spreading the news about the incident response plan c. installing new hard disks d. increasing access controls

Write a new lc-3 trap subroutine (i.e. a subroutine that will be invoked via the trap instruction) that will receive a numeric digit entered at the keyboard (i.e. an ascii character), echo it to the screen, and return in r0 the corresponding numeric value: so if the user types the digit '7', the character '7' will appear on the screen, but the value returned in r0 will be b0000 0000 0000 0111 (#7) you may not use any trap calls in your code - you must implement the "polling" code that interrogates the keyboard status and data registers. ; getnum_tsr ; a subroutine for obtaining a numeric value ; given ascii numeric digit input to keyboard. ; the numeric digit is echoed to the console (e.g. '7' = b0000 0000 0011 0111), ; but the value returned in r0 is the actual numeric value ; corresponding to the digit (e.g. b0000 0000 0000 0111 =