Python: Retype and run, note incorrect behavior. Then fix errors in the code, which should print num_stars asterisks.
while num_printed != num_stars:
print('*')
Sample output with input: 3
*
*
*

num_printed = 0

num_stars = int(input())

''' Your solution goes here '''

Acomputer has a two-level cache. suppose that 60% of the memory references hit on the first level cache, 35% hit on the second level, and 5% miss. the access times are 5 nsec, 15 nsec, and 60 nsec, respectively, where the times for the level 2 cache and memory start counting at the moment it is known that they are needed (e.g., a level 2 cache access does not even start until the level 1 cache miss occurs). what is the average access time?