A digital signaling system is required to operate at 9600 bps. a. If a signal element encodes a 4-bit word, what is the minimum required bandwidth of the channel

1200 Hz

Explanation:

Given that the signal encodes 4-bit words, then

log2M = 4,

Again, we're told that the system operates at 9600 bps, so

C = 9600

If we bring back our earlier relation, we have

9600 = 2B * 4

9600 = 8B

B = 9600 / 8

B = 1200 Hz

Therefore, we can conclude that the minimum required bandwidth of the channel is 1200 Hz

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