Use the factorial operation to evaluate 10!. A) 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
B) 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
C) 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
D) 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

D

Explanation:

The definition of n! is n x (n-1) x (n-2) x ... x 1.

So 10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 i.e. D.

D) 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

Explanation:

The problem here is to use the factorial method to find;

    10!

The factorial of any number is given as:

       a!  = (a - 1) x (a - 2) (a - n)

It is the product of any integer from 1 to that number.

So;

   10!   = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

The solution is therefore 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

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