Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with

Question:

Write a program that reads a list of integers, and outputs whether the list contains all even numbers, odd numbers, or neither. The input begins with an integer indicating the number of integers that follow. Assume that the list will always contain less than 20 integers.

Written in Python

listlent = int(input("Length of List: "))

mylist = []

mylist.append(listlent)

for i in range(listlent):

    num = int(input(": "))

    mylist.append(num)

evens = 0

odds = 0

for i in range(1,listlent+1):

    if mylist[i]%2==0:

         evens=evens+1

    else:

         odds=odds+1

if(evens == 0 and odds != 0):

    print("All Odds")

elif(evens != 0 and odds == 0):

    print("All Even")

else:

    print("Neither")

Explanation:

This prompts user for length of the list

listlent = int(input("Length of List: "))

This initializes an empty list

mylist = []

The following iteration reads the list items from the user

mylist.append(listlent)

for i in range(listlent):

    num = int(input(": "))

    mylist.append(num)

The next two lines initialize even and odd to 0, respectively

evens = 0

odds = 0

The following iteration if a list item is even or odd

for i in range(1,listlent+1):

    if mylist[i]%2==0:

         evens=evens+1

    else:

         odds=odds+1

This checks and prints if all list items is odd        

if(evens == 0 and odds != 0):

    print("All Odds")

This checks and prints if all list items is even        

elif(evens != 0 and odds == 0):

    print("All Even")

This checks and prints if all list items is neither even nor odd

else:

    print("Neither")

i would say 3 because windows is the best but vista doesnt do updates anymore