Given positive integer num_insects, write a while loop that prints that number doubled up to, but without exceeding 100. Follow each number with a space. Sample output with input: 8
8 16 32 64
Here's what I havenum_insects = 8 # Must be >= 1print(num_insects, '', end='')while num_insects <= 100 : num_insects = num_insects * 2 print(num_insects,'', end="")This code prints the number 128 even thought the loop is set to end after 100? Why is that?

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }