Write a function (funception) that takes in another function func_a and a number start and returns a function (func_b) that will have one parameter to take in the stop value. func_b should take the following into consideration the following in order: Takes in the stop value. If the value of start is less than 0, it should exit the function. If the value of start is greater than stop, apply func_a on start and return the result. If not, apply func_a on all the numbers from start (inclusive) up to stop (exclusive) and return the product.

The code for this question can be defined as follows:

def funception(func_a, start):#define a method funception that accept two parameter

   def func_b(stop): #define a method func_b that accept one parameter

       if start < 0:#define if block that checks start parameter value less then 0

           return #Use return keyword

       if start > stop:#define if block that checks start parameter value greater then stop parameter value

           return func_a(start)#use return keyword to call func_a method

       else:#define else block

           product = 1#define a variable product and assign a value 1

           for i in range(start, stop):#define for loop to calculate the value

               product= product * func_a(i)#multiply the method value in product variable

           return product#return prod value

   return func_b#return func_b value

def func_a(num):#define a method func_a that accept a num variable as a parameter

   return num + 1#use return keyword by increment num value by 1

Explanation:

In the above python program code, a method "funception" is defined that accepts two parameters that are "func_a and start", in which "func_a" is a method name, that accepts a "num" variable in its parameter and returns its one increment value.

answer: 2 min

explanation:

they run fast