subject

A) Given a sorted array, write the fastest algorithm (measured by worst case big O) to print all values greater than a given x and less than a give y. Assume that x and y are both in the array. b) Assuming you have k integers in that range and it takes one unit of time to print an integer, what is the worst case running time of your algorithm?
Note 1: You can describe the algorithm in English sentences or you can write a pseudo-code. You do not need to write a JAVA code.

ansver
Answers: 1

Another question on Computers and Technology

question
Computers and Technology, 23.06.2019 18:30
Report all segments of identity by descent longer than 20 polymorphisms between pairs of individuals in the following cohort of 15 individuals across 49 polymorphisms: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 numeric input 2 points possible (graded) you have 2 attempts to complete the assignment below. for example if the sequence is "bcd", which occurs in "abcdef" , the starting point would be 2 (b), and the finishing point would be 4(d). individuals 7,10 between positions
Answers: 1
question
Computers and Technology, 24.06.2019 08:30
Aconsumer would pay an extra they used the rent to own program to buy the computer, rather than using cash. for all of the items, is the cheapest option over the life of the contract. the most expensive overall option is to use purchase the item.
Answers: 2
question
Computers and Technology, 24.06.2019 12:50
When is it most apprpriate for a development team to change the definition of done
Answers: 1
question
Computers and Technology, 24.06.2019 18:20
The following if statement contains a logic error, not a syntax error. rewrite it so that it is correct. assume the variable age already exists and holds a valid number. if (age == 18 & & age == 19) {
Answers: 1
You know the right answer?
A) Given a sorted array, write the fastest algorithm (measured by worst case big O) to print all val...
Questions
question
History, 30.12.2020 04:20
question
Social Studies, 30.12.2020 04:20
question
Mathematics, 30.12.2020 04:20