Write a program that could find whether the number entered through keyboard is odd or even the program should keep on taking the value till the user ends.

using namespace std;

int main() {

int number;

while (1) {

 cout << "Enter a number: ";

 cin >> number;

 cout << number << " is " << ((number % 2) ? "odd" : "even") << endl;

};

return 0;

}

Explanation:

This is a c++ version. Let me know if you need other languages.

The (number % 2) is the essence of the program. It returns 0 for even numbers, and 1 for odd numbers (the remainder after division by 2).

the answer is gallery.