Given an IP address and mask of 192.168.0.0 /24 (address / mask), design an IP addressing scheme that satisfies the following requirements. Network address/mask and the number of hosts for Subnets A and B will be provided by your instructor. Subnet
Number of Hosts
Subnet A
55
Subnet B
25
The 0th subnet is used. No subnet calculators may be used. All work must be shown on the other side of this page.
Subnet A
Specification
Student Input
Points
Number of bits in the subnet
2
(5 points)
IP mask (binary)
11111111.11111111.11111111.11000000
New IP mask (decimal)
255.255.255.192
Maximum number of usable subnets (including the 0th subnet)
4
Number of usable hosts per subnet
62
IP Subnet
192.168.0.0/26
First IP Host address
192.168.0.1
Last IP Host address
192.168.0.62
Subnet B
Specification
Student Input
Points
Number of bits in the subnet
5
(5 points)
IP mask (binary)
11111111.11111111.11111111.11100000
New IP mask (decimal)
255.255.255.224
Maximum number of usable subnets (including the 0th subnet)
8
Number of usable hosts per subnet
30
IP Subnet
192.168.0.64/27
First IP Host address
Last IP Host address
Host computers will use the first IP address in the subnet. The network router will use the LAST network host address. The switch will use the second to the last network host address.
Write down the IP address information for each device:
Device
IP address
Subnet Mask
Gateway
Points
PC-A
192.168.0.1
255.255.255.192
192.168.0.63
(5 points)
R1-G0/0
192.168.0.63
255.255.255.192
N/A
R1-G0/1
192.168.0.95
255.255.255.224
N/A
S1
192.168.0.94
255.255.255.224
N/A
PC-B
192.168.0.65
255.255.255.224
192.168.0.95
Before proceeding, verify your IP addresses with the instructor.
Can you double-check and provide the First and Last Ip address?