Write a statement that assigns total_coins with the sum of nickel_count and dime_count. Sample output for 100 nickels and 200 dimes is: 300

The statement which gives the sum of nickel and dime is written below :

total_coins = nickel_count + dime_count

The statement required is written using Python 3 :

def total(nickel_count, dime_count) :

total_coins = dime_count + nickel_count

print(total_coins)

total(100, 200)

#the function total takes in two arguments(number of nickels and number of dimes)

#assigns the varibale total_coins to the sum of nickel_count and dime_count

nickel_count = int(input('Enter count of nickel : '))

# User is prompted to enter number of nickels

dime_count = int(input('Enter count of dime : '))

# User is prompted to enter number of dimes

total_coins = nickel_count + dime_count

#assigns the varibale total_coins to the sum of nickel_count and dime_count

print(total_coins)

#outputs the value of total_coins

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total_coins = nickel_count + dime_count

Explanation:

The statement that performs the operation in the question is total_coins = nickel_count + dime_count

Full Program (Written in Python)

nickel_count = int(input("Nickel Count: "))

dime_count = int(input("Dime Count: "))

total_coins = nickel_count + dime_count

print("Total coins: ",total_coins)

The first two lines prompt user for nickel and dime count respectively

The third line adds the two coins categories together

The last line prints the total count of coins

answer: 2 min

explanation:

they run fast

solution:

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