Write a method max() which take a generic singly linked list as an argument and returns the maximum element reference in the list. If the list is empty, please throw an empty collection exception. The method prototype is defined as follows. public static > T max(SingleLinkedList list) throws EmptyCollectionException.

See explaination

Explanation:

java code:

class DONALD

{

static class Node

{

int data;

Node next;

}

static Node head=null;

static int largestElement(Node head)

{

Int max=Integer.MIN_VALUE;

while(head!=null)

{

if(max<head.data)

max=head.data;

head=head.next;

}

return max;

}

static int smallestElement(Node head)

{

int min=Integer.MAX_VALUE;

while(head!=null)

{

if(min>head.data)

min=head.data;

head=head.next;

}

return min;

}

static void push(int data)

{

Node newNode=new Node();

newNode.data= data;

newNode.next=(head);

(head)=newNode;

}

static void printList(Node head)

{

while(head!=null)

{

System.out.println(head.data + " -> ");

head=head.next;

}

System.out.println("NULL");

}

public static void main(String[] args)

push(15);

push(14);

push(13);

push(22);

push(17);

System.out.println("Linked list is : ");

printList(head);

System.out.println("Maximum element in linked list: ");

System.out.println(largestelement(head));

System.out.print("Maximum element in Linked List: " );

System.out.print(smallestElement(head));

}

}