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Cosx+2=−x3+3x Using Newton's method as discussed in the lecture, find the value of x for which f(x∗)=0. Your answer should be real; increase the tolerance to verify if any imaginary components go to zero. For reference, this is the code we developed. You may also import and use scipy. optimize. newton if you prefer. A version of this question will be asked on a future quiz. def dfdx( f, x,h=1e-3 ): return ( f( x+h ) - f( x ) ) / h def newton( f, x0,tol=1e-3 ): d = abs( 0 - f( x0 ) ) while d > tol: x0 = x0 - f( x0 ) / dfdx( f, x0 ) d = abs( 0 - f( x0 ) ) return ( x0,f( x0 ) )
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Cosx+2=−x3+3x Using Newton's method as discussed in the lecture, find the value of x for which f(x∗)...
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