In this lab, you will develop a game, "Tic Tac Toe". Assume there are two players; the computer and theuser.Initially you will create the board, a 3x3 matrix, and fill it out with zeros.Ask user to start first, and record the user’s input as 1You can ask the user to enter the row first than the column (for ex; the user can enter 2 and 1,then the code shouldupdate the value of second row first column)The computer should make random moves, and the computer input should be recorded as 2After each move, check if someone wins, and display the boardDisplay the result (who wins and the board)Create as much helper functions as needed.Divide and ConquerSampleRun:board = [[0,0, 0],[0,0, 0],[0,0,0]]enter the row;2enter the column;1board = [[0,0, 0],[1,0, 0],[0,0,0]]the computer playsboard = [[0,2, 0],[1,0,0],[0,0,0]]CS103-Lab9Page4o f6enter the row;2enter the column;2board = [[0,2, 0],[1,1, 0],[0,0,0]]the computer playsboard = [[0,2, 0],[1,1, 0],[0,0,2]]enter the row;2enter the column;3board = [[0,2, 0],[1,1,1],[0,0,2]]Game Over Winner: The User

Code:

# importing all necessary libraries

import numpy as np

import random

# Select a random place for the player

def play(board, player):

selection = availableSpots(board)

if player==1:

row=(int)(input("Enter the row :"))

column=(int)(input("Enter the column :"))

current_loc=(row-1,column-1)

while current_loc not in selection:

print("Invalid Input. Please give again")

row=(int)(input("Enter the row :"))

column=(int)(input("Enter the column :"))

current_loc=(row-1,column-1)

else:

current_loc = random.choice(selection)

board[current_loc] = player

return board

# Check for empty places on board

def availableSpots(board):

  l = []

  for i in range(len(board)):

      for j in range(len(board)):

          if board[i][j] == 0:

              l.append((i, j))

  return(l)

# Creates an empty board

def create_board():

  return(np.array([[0, 0, 0],

                  [0, 0, 0],

                  [0, 0, 0]]))

# Checks whether the player has three

# of their marks in a horizontal row

def row_win(board, player):

  for x in range(len(board)):

      win = True

      for y in range(len(board)):

          if board[x, y] != player:

              win = False

              continue

      if win == True:

          return(win)

  return(win)

# Checks whether the player has three

# of their marks in a vertical row

def col_win(board, player):

  for x in range(len(board)):

      win = True

      for y in range(len(board)):

          if board[y][x] != player:

              win = False

              continue

      if win == True:

          return(win)

  return(win)

# Checks whether the player has three

# of their marks in a diagonal row

def diag_win(board, player):

  win = True

  for x in range(len(board)):

      if board[x, x] != player:

          win = False

  return(win)

# Evaluates whether there is

# a winner or a tie

def evaluate(board):

  winner = 0

  for player in [1, 2]:

      if (row_win(board, player) or

          col_win(board,player) or

          diag_win(board,player)):

          winner = player

  if np.all(board != 0) and winner == 0:

      winner = -1

  return winner

def printWinner(winner):

print("Game Over !!!")

if winner==1:

print("Player Wins")

elif winner==2:

print("Computer Wins")

else:

print("Nobody Wins")

# Main function to start the game

def play_game():

board, winner = create_board(), 0

print(board)

while winner == 0:

for player in [1, 2]:

board = play(board, player)

print("Board")

print(board)

winner = evaluate(board)

if winner != 0:

break

printWinner(winner)

play_game()

Explanation:

See screen shot of code and see final output

the answer is:

c) organizational chart

hope it !