What is displayed on the console when running the following program? class Test { public static void main(String[] args) { try { method(); System. out. println("After the method call"); } catch (RuntimeException ex) { System. out. println("RuntimeException"); } catch (Exception ex) { System. out. println("Exception"); } } static void method() throws Exception { try { String s = "5.6"; Integer. parseInt(s); // Cause a NumberFormatException int i = 0; int y = 2 / i; System. out. println("Welcome to Java"); } catch (RuntimeException ex) { System. out. println("RuntimeException"); } catch (Exception ex) { System. out. println("Exception"); } } } Question 8 options:

RuntimeException

After the method call

Explanation:

Image showing the program output when executed is attached.

In the code snippet given, inside the main method which is the beginning of program execution, there is a try-catch blocks.

The try block is executed first and the catch block is only executed if an exception is thrown.

The try block has two statement to execute:

try {

        method();

        System.out.println("After the method call");

}

The first statement is executed by calling the method called method(). The second statement display the output: "After the method call".

When method() is called, a runtime exception is thrown and a catch block is executed which display the message: "RuntimeException".

runtime exception occur during the program execution. From the above code snippet, the runtime exception is thrown/caused by the line below:

Integer.parseInt(s);

It is cause because the when the string is converted to integer, it is not assigned to any variable and this lead to the runtime exception.

explanation:

so if you are under a school block you cant but it may also be do to you having to add it to your chrome book like an app like i did or its the wifi you have blocking it

answer; i believe that technician b is correct;