Write a for loop to print all NUM_VALS elements of vector courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1.#include using namespace std;int main() {const int NUM_VALS = 4;int courseGrades[NUM_VALS];int i = 0;courseGrades[0] = 7;courseGrades[1] = 9;courseGrades[2] = 11;courseGrades[3] = 10;//Your solution goes here

#include <iostream>

using namespace std;

int main()

{

int courseGrades [ ] = {7, 9, 11, 10};

for(int i =0; i<4; i++){

       cout<<courseGrades[i]<<" ";

}

for(int j = 3; j>=0; j--){

   cout<<courseGrades[j]<<" ";

}

}

Explanation:

Using C++ programming language

Create the array vector and assign values with this statement int courseGrades [ ] = {7, 9, 11, 10};

The first for loop prints the values from 0-4 (Since four values are given and hard coded) for(int i =0; i<4; i++)

The second for loop prints from the last to the first element (i.e reversed) for(int j = 3; j>=0; j--)

the correct option is (d) vin label

vin stands for vehicle information number. this is a thin metallic plate attached to the engine of the vehicle and it includes all the important information which are related to the vehicle. it also provides the information whether the vehicle has been stolen or not because the replacement and alternation of vin number creates difference in the exact number printed on the vin and carved on the engine.