Given the network 192.168.4.0/24, we are going to segment this network into two subnets, Subnet A and Subnet B. The hosts requirement for Subnet A is 60 and for Subnet B is 10. Please calculate the new subnet masks for each subnet and fill in the tables below:

Subnet A:

Subnet Mask
Number of Useable Hosts in this Subnet
IP Network Address
First valid IP Address
Last valid IP Address
Subnet Broadcast IP Address

Subnet B:

Subnet Mask
Number of Useable Hosts in this Subnet
IP Network Address
First valid IP Address
Last valid IP Address
Subnet Broadcast IP Address

Answer / Explanation:

For proper understanding, let us define what a Subnet is:  Subnet which is also sometimes refereed to as a  is a logical subdivision of an IP network is described as the act of segmenting a network into two or more networks is called sub-netting. Computers that belong to a subnet are addressed with an identical bit-group in their IP addresses.

In respect to the definition above, if we go ahead to calculate the new subnet masks for each sub net below, we have:

Subnet A                                                                    Answer

Subnet Mask in Decimal (3 points)                  255.255.255.192

Subnet Mask in Binary (2 points)               1111111.11111111.11111111.11000000

Number of Useable Hosts in this Subnet             62 available hosts

IP Network Address (2 points)                                   192.168.4.0

First valid IP Address (2 points)                                    192.168.4.1

Last valid IP Address (2 points)                                    192.168.4.62

Subnet   Broadcast   IP   Address   (2points)                192.168.4.63

Subnet B                                                                             Answer

Subnet Mask in Decimal (3 points)                           255.255.255.240

Subnet Mask in Binary (2 points)                       1111111.11111111.11111111.11110000

Number of Useable Hosts in this Subnet                                14

IP Network Address (2 points)                                          192.168.4.64

First valid IP Address (2 points)                                         192.168.4.65

Last valid IP Address (2 points)                                            192.168.4.78

Subnet  Broadcast IP Address                                              192.168.4.79

c a goverment agency or homeowner

answerthe above statement is (false);