Draw a flow chart and write pseudocode for an iterative algorithm that calculates 1 - 1/2 +1/3 - +(or -) 1/n. 1/k is added to the sum if k is odd and subtracted from the sum if k is even. (this sum converges in 2, the natural logarithm of 2).

PSEUDOCODE

BEGIN

A = 0

n = 1

Input Number

Loop :

do while n <= Number

A = A + (-1)^(n+1) * (1/n)

n = n + 1

return to loop

print A

END

See attachment for Flowchart

Explanation:

Assume number = 3

First Loop : A = 0 + (-1)^2 * 1/1 = 1

Second Loop : A = 1 and n = 2

A = 1 + (-1)^(2+1) * 1/2 = 1 - 1/2

Third Loop : A = 1 - 1/2 and n = 3

A = 1 - 1/2 (-1)^(3+1) * 1/3 = 1 - 1/2 + 1/3

Print A will then print 5/6

the answer to your question would be something called hertz. the unit of measurement called a hertz, which is one cycle per second, is used to measure clock speed. within one cycle, your computer processes, refreshes, or updates itself to the changes that it is going through. in the case of computer clock speed, one hertz equals one tick per second. the clock speed of computers is usually measured in megahertz (mhz) or gigahertz (ghz)