Needed in c++ programming!

on a piano, each key has a frequency, and each subsequent key (black or white) is a known amount higher. ex: the a key above middle c key has a frequency of 440 hz. each subsequent key (black or white) has a frequency of 440 * rn, where n is the number of keys from that a key, and r is 2(1/12). given an initial frequency, output that frequency and the next 3 higher key frequencies. if the input is 440, the output is: 440 493.883 523.251 554.365.

note: include one statement to compute r = 2(1/12) using the pow function, then use r in the formula fn = f0 * rn. (you'll have three statements using that formula, different only in the value for n).

This program is executed in C++ using dev C++, The explanation of the code is given below. However, the expected result of this program after running is attached

Explanation:

#include <iostream>

#include <cmath>

#include<bits/stdc++.h>

using namespace std;

int main ()

{

double key=5;//it will generate next three keys from A;

double freq=440;//frequency ;

cout<<freq<<"     ";//output the frequency

for(double i=2;i<key;i++)//loop to show next three frequency

{

float value = (1.0/12);// store value of (1/12)

double r=pow(2.0,value);//store value of r=2^(1/12);

double n=i;//number of ith iteration (number of next key)

double power=pow(r,n);//calculating r^n;

double result= freq* power;//function i.e. fn=f0*rn

cout<<result<<"     ";//displaying result

}

}

nope i prefer two because it is simpler, i don't like all the powers you get

explanation:

but that's my opinion

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