Areceiver requires 10nw as input power. if all the system losses add up to 50db, then how much power is required from the source.

Gain (dB)=10 log(O.P./I.P)

Also, the loss(dB) = -gain(dB) = 10 log(I.P/O.P)

which is, 50 = 10 log(I.P./10nW)

and hence, anti-log(5) = I.P/10 nW

And thus the power required by the source is antilog(5)*10nW = 1 mW

Note: Power required by the receiver is the O.P. and the power required from the source is the I.P.

Explanation:

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