Write a function which the counts the number of odd numbers and even numbers currently in the stack and prints the results.

See the code below and the algorithm explanation on the figure.

Explanation:

The explanation in order to get the answer is given on the figure below.

Solving this problem with C. The program is given below:

#include <stdio.h>

int main(void) {

   int n, Even=0, Odd=0, Zeros=0;  

   for (;;) {

       printf("\nEnter the value the value that you want to check(remember just integers): ");

       //IF we input a non-numeric character the code end;

       if (scanf("%d", &n) != 1) break;

       if (n == 0) {

           Zeros++;

       }

       else {

           if (n % 2) {

               Even++;

           }

           else {

               Odd++;

           }

       }

   }  

   printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);

   return 0;

}

2b2t

explanation:

2b2t