Write a function safeopen() that takes one parameter, filename — a string giving the pathname of the file to be opened for reading. when safeopen() is used to open a file, a reference to the opened file object should be returned if no exception is raised, just like for the open() function. if an exception is raised while trying to open the file, safeopen() should return the value none.

post   it and ill go to your page to answer it to my best

explanation:

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.