Write a function that given an integer n(1< =n< =100) returns an array containing n distinct integers that sum up to 0. the function can return any such array. for example, given n=4, the function could return (1,0,-3, 2], and for n=3 one of the possible answers is [-1,0,1] (but there are many more correct answers)

Explanation:

This is simple. I We begin by creating 2 groups of equal and opposite. The total number of elements in both group is N (if N is even) or N-1(if N is odd). The total value of both group should equal to 0. Add 0 if N is odd

We can code this function in python

def array_maker(N):

    if N % 2 == 1:

         if N == 1: # special case

              return [0]

         else:

              left_ray = [i for i in range(-N//2, 1)]

              right_ray = [i for i in range(N//2)]

              left_ray.extend(right_ray)

              return left_ray

    else:

         left_ray = [i for i in range(-N/2, 0)]

         right_ray = [i for i in range(N/2)]

         left_ray.extend(right_ray)

         return left_ray

yes, but you must first make sure that you'll be able to make your turn or you can crash into other vehicles.

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