Ask the user to input an integer. print out the next three consecutive numbers. in python

Assume that you have an array of integers named a. which of these code segments print the same results? int i = 1; while(i < a.length) { system.out.println(a[i]); i++; } int i; for (i = 0; i < a.length; i++) { system.out.println(a[i]); } for (int i : a) { system.out.println(i); } i and ii only ii and iii only i and iii only all three print the same results. all three print different results.

Given the following code: if (n == 2) { k -= 2; } else if (n == 3) { k -= 3; } can be rewritten as: if (< condition > ) { < assignment statement > ; } assume that evaluating < condition > does not change the values stored in n and k. which of the following could be used as < assignment statement > ? k -= n; k -= 1; k -= 2; k += n; k = n - k;

Your program will make use of long long int variables for all calculations. note: the use of long long int requires that you have c++11 support. you should have this automatically if you are using a newer version of visual studio. the support is there for gcc as well, but you may need the -std=c++11 or -std=c++0x compiler flag. you first need to read in the total number of seconds. there is no prompt for the read (that is, you just do the cin without using a cout to display a prompt). this is going to seem a little strange when you are running your program in your ide