Write a script that checks each minute and reports on who logs in and who logs out. you can follow the steps below (not the only way): 1. using the commands who and cut, extract the list of usernames currently logged in the system 2. to check after a minute, the sleep command can be used: sleep 60 3. get the new list of users logged in after a minute 4. for each user in the first list, check if he is in the second list using if and grep. you can dump the output of grep to /dev/null when using it in the as a test for the if statement if the user is not in the second list, print that the user has logged out a. b. 5. for each user in the second list, a. if he is in the first list, print that the user has logged in 6. 7. rename the second list as the first list repeat the process from step 2)

The answer for  the test  is d. 20.7

(java)3. the answer is  (c): x[2] = 12; if x is an array with three elements, the first element has index 0. the second index has index 1. the third and final element has index 2.4. the answer is (d) for (int y : x) { system.out.println (y) ; }this is an example of syntax  of a "for-each loop."for each element in the integer array x, use y to indicate the current element to do some code with it.the other choice, (c) for (int x : y) { system.out.println (y) ; }. in a for-each loop, the variable to the right of the colon is the array variable; the one to the left is the control variable.choices (a) and (b) have invalid syntax.5. the answer is (a)  int x = {1, 2, 3, 5, 10}; you need to indicate that it is an array using []. without using [], you are trying to assign an array to an integer. you need to use int[] to indicate integer array.so choice (a) has incorrect syntax.

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