Concerning e-mails, or electronic communications being sent to clients, all of the following are false except: (a) as long as the number of clients receiving the e-mail does not exceed 25 or more existing clients principal approval is not necessary. (b) as long as the sender of the electronic communication is properly trained, review is not necessaryat anytime before such communications are sent. (c) since e-mail is not considered a formal form of communication, no review is ever necessary. (d) all e-mails must be reviewed prior to issuance by a principal.

Suppose we have a byte addressable computer that has a 32-byte cache with 8 bytes per block. the memory address is 8 bits long. the system accesses memory addresses (in hex) in this exact order: 6e, b9, 17, e0, 4e, 4f, 50, 91, a8, ab, ad, 93, and 94. (a) assuming the cache is direct mapped, what memory addresses will be in cache block 2 after the last address has been accessed? (b) assuming the cache is direct mapped, what is the hit ratio for the entire memory reference sequence given, assuming the cache is initially empty? (c) assuming the cache is 2-way set associative with a lru replacement policy, what is the hit ratio?

The best definition of an idiom is a. a word or phrase that describes a noun b. a word or phrase describing a verb c. a phrase containing figurative language in which the word expresses a different idea from its exact meaning d. a phrase that compares two unlike objects or ideas

Create a string list. 2. use console.readline() to collect values of firstname, lastname, street, city, state, zip, save them to list. 3. write a simple linq statement, call method uppercasewords() to change first letter to uppercase. 4. create a foreach statment to display the information. public static string uppercasewords(string value) { char[] array = value.tochararray(); if (array.length > = 1) { if (char.islower(array[0])) { array[0] = char.toupper(array[0]); } } for (int i = 1; i < array.length; i++) { if (array[i - 1] == ' ') { if (char.islower(array[i])) { array[i] = char.toupper(array[i]); } } } return new string(array);