What is the output of executing the code segment?

a, b, c = false, true, false

if a or b:

print('a', end = ' ')

else:

print('b', end = ' ')

if not b:

print('c', end = ' ' )

elif c :

print('d', end = ' ' )

else:

print('e', end = ' ' )

print()

a) a e

b) b e

c) a

d) none of the above

Correct option is (a) that is: A E

Explanation:

In the first if condition we are checking "if a or b" ,that means if any of both is true then it will print "A" and here value of "b" is "True".Therefore A will be printed first.Next else condition will not execute.Value of "b" if "True" and in the next if condition "if not b" will be "False" so next statement will not execute. Similarly "elif c" condition will be "False" because value of "c" is "False".Therefore next line will not execute and else part executes and print "E" in the same line.So the whole code will print A E in one line.

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posting this in wrong category will result in people seeing it who won't know the answer.

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