Acomputer’s memory is composed of 8k words of 32 bits each. how many bits are required for memory addressing if the smallest addressable memory unit is a word?
13
8
10
6
32

The minimum number of bits necessary to address 8K words is 13.

Explanation:

You have the number of words to address that is 8000 words, a word is the smallest addressable memory unit.  

8000 words can be addressed with  units. Now you have to find the value of n that approximates to the number of words.  

So you can see that 13 bits are needed to address 8K words.

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