Write code to print the location of any alphabetic character in the 2-character string passcode. each alphabetic character detected should print a separate statement followed by a newline. ex: if passcode is "9a", output is: alphabetic at 1 hint: use two if statements to check each of the two characters in the string, using character.

// here is code in java.

import java.util.*;

//class defintion

class Main

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // scanner object to read input

       Scanner s=new Scanner(System.in);

       String passcode;

       System.out.print("please enter the passcode:");

       // read string from user

       passcode=s.nextLine();

       // find first character

       char ch=passcode.charAt(0);

       // find second character

       char ch1=passcode.charAt(1);

       // if first character is alphabet

       if(Character.isLetter(ch))

       System.out.println("Alphabetic at 0:");

       // if second character is alphabet  

      else if(Character.isLetter(ch1))

       System.out.println("Alphabetic at 1:");

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create a scanner class object to read input from user.Read 2-character string

from user.Find the each character and check if it is a alphabet or not.If First

character is alphabet then print "Alphabetic at 0:" else if second character

is alphabet then print "Alphabetic at 1:".

Output:

please enter the passcode:b2

Alphabetic at 0:

answer; i believe the above is false;

answer; i do believe its (faster);