When troubleshooting firewalls, you should never attempt to repeat the problem because you could do more damage. truefalse

4. does the kernel phenotype distribution support the idea that the cob is the result of a dihybrid cross? what information supports your answer? if a dihybrid cross (i.e. f1 to f2 of standard mendelian crosses) is not indicated what conditions might contribute to this finding.

Create a string list. 2. use console.readline() to collect values of firstname, lastname, street, city, state, zip, save them to list. 3. write a simple linq statement, call method uppercasewords() to change first letter to uppercase. 4. create a foreach statment to display the information. public static string uppercasewords(string value) { char[] array = value.tochararray(); if (array.length > = 1) { if (char.islower(array[0])) { array[0] = char.toupper(array[0]); } } for (int i = 1; i < array.length; i++) { if (array[i - 1] == ' ') { if (char.islower(array[i])) { array[i] = char.toupper(array[i]); } } } return new string(array);

Acommon algorithm for converting a decimal number to binary is to repeatedly divide the decimal number by 2 and save the remainder. this division is continued until the result is zero. then, each of the remainders that have been saved are used to construct the binary number.write a recursive java method that implements this algorithm.it will accept a value of int and return a string with the appropriate binary character representation of the decimal number.my code: public class lab16{public string converttobinary(int input){int a; if(input > 0){a = input % 2; return (converttobinary(input / 2) + "" +a); } return ""; } }