How is ( a || b ) & & c || ( a || b ) & & ( ! c ) equal to ( a || b ) without simplification?

You can see the truth table in the image.

Explanation:We can do this question by using truth table.

As we can see in the truth table that there is no effect on the output of the expression by c if a and b both are false then the output is false and if any of them is True or both of them are True then the result is True.

maybe when you are listing people names in a job.

i am not 100% sure

answerthe above statement is (false);