Agas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kpa. what volume will the gas occupy if the temperature is increased to 400.0 k and the pressure is increased to 200.0kpa

According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure,  T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have


Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = 
∴ V2 = 4 m3 

Rate law for this reaction israte of the reaction = k[a]²[b].second order in a  means concentration of a in power of two, and  first order in b means concentration of b in power of one.

It must be measured in k.hope my answer is to you : )