Chemistry, 21.07.2019 11:30 Chynadoll94

Which of these do not obey the octet rule? select all that apply. select all that apply. clo clo− clo2− clo3− clo4−?

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$\boxed{{\text{ClO,ClO}}_{\text{2}}^ - {\text{,ClO}}_{\text{3}}^ - {\text{,ClO}}_{\text{4}}^ - }$ does not follow the octet rule.

Further Explanation:

Octet rule: states that for the stability of any element it must have a valence shell of eight electrons (octet means a group of eight). This rule is given by Kossel and Lewis.

Atoms of same or different elements with an incomplete electronic configuration that is having electrons less than 8 are unstable and they combine together to form stable molecules with a complete octet. They can combine by sharing of electrons or loss or gain of electrons.

In ${\mathbf{ClO}}$ , Chlorine (Cl) has 7 electrons in its outer shell and oxygen has 6 electrons in its outer shell. So chlorine and oxygen share 2 electrons each to complete their octet and attain stability. Chlorine atom in the compound has ten electrons in its outer shell so it doesn’t follow the octet rule.

In ${\mathbf{Cl}}{{\mathbf{O}}^ - }$ , Chlorine(Cl) has 7 electrons in its outer shell and oxygen has a unit negative charge on it $\left( {{{\text{O}}^ - }} \right)$ so, it has 7 electrons also in its outer shell. So chlorine and oxygen share one electron each to complete their octet and attain stability. All the atoms have eight electrons in their outer shell so they follow the octet rule.

In ${\mathbf{ClO}}_2^ -$ , Chlorine (Cl) has 7 electrons in its outer shell and there is 2 oxygen attached to Cl. One has a unit negative charge on it $\left( {{{\text{O}}^ - }} \right)$ and the other is neutral. So, chlorine and neutral oxygen share 2 electrons each to get a stable octet and form a double bond. Similarly, chlorine shares 1 electron with oxygen ion with a negative charge on it forming a single bond with it. A chlorine atom has ten electrons in its outer shell so the compound doesn’t follow the octet rule.

In ${\mathbf{ClO}}_3^ -$ , Chlorine (Cl) has 7 electrons in its outer shell and there is 3 oxygen attached to Cl. One has a unit negative charge on it $\left( {{{\text{O}}^ - }} \right)$ and the other two are neutral. So, chlorine and both neutral oxygen share 2 electrons to get a stable octet and form a double bond. Similarly, chlorine shares 1 electron with oxygen ion with a negative charge on it, forming a single bond with it. Here, Cl has ten electrons in its outer shell, so it doesn’t follow the octet rule.

In ${\mathbf{ClO}}_4^ -$ , Chlorine (Cl) has 7 electrons in its outer shell and there is 4 oxygen attached to Cl. One has a unit negative charge $\left( {{{\text{O}}^ - }} \right)$ on it and the other three are neutral. So, chlorine and both neutral oxygen share 2 electrons to get a stable octet and form a double bond. Similarly, chlorine shares 1 electron with oxygen ion with a negative charge on it, forming a single bond with it.

Here, Cl has fourteen electrons in its outer shell, so it doesn’t follow the octet rule.

Learn more:

1. The octet rule states that:link

2. How many covalent bond nitrogen forms: link

Answer details:

Grade: Secondary School

Subject: Chemistry

Chapter: Chemical Bonding

Keywords: octet rule, stability, oxygen, chlorine, covalent, sharing, ClO2-, ClO3-, ClO4-, ClO-and ClO.

Answer from: Quest

Where are the questions

Answer from: Quest

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

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Which of these do not obey the octet rule? select all that apply. select all that apply. clo clo− c...

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