What is the celsius temperature of 100.0 g of chlorine gas in a 55.0-l container at 800 mm hg?

Given, pressure = P = 800 mm Hg = 1.066 X 10^5 Pa
Volume = V = 55 l = 0.055 m^3
number of moles of Cl2 gas = n =  =  = 1.408

Now, based on ideal gas equation, we have
PV=nRT
∴ T = PV/RT
where R = universal gas constant = 8.314 J /mol K
∴ T =  = 500.8 K

Now, we know that 
∴ 500.8 K =