Aluminum metal reacts with hcl to produce aluminum chloride and hydrogen gas. how many grams of aluminum metal must be added to an excess of hcl to produce 33.6 l of hydrogen gas, if the gas is at stp?
(a) 18.0 g
(b) 35.0 g
(c) 27.0 g
(d) 4.50 g
(e) 9.00 g

The mass of aluminium metal that must be added is 27.0 grams

Explanation:

We are given:

Volume of hydrogen gas = 33.6 L

At STP conditions:

22.4 L of volume is occupied by 1 mole of a gas

So, 33.6 L of volume will be occupied by = of hydrogen gas

The chemical equation for the reaction of aluminium metal and HCl follows:

By Stoichiometry of the reaction:

3 moles of hydrogen gas is formed by 2 moles of aluminium metal

So, 1.5 moles of hydrogen gas will be formed by = mole of aluminium metal

To calculate the number of moles, we use the equation:

Moles of aluminium metal = 1 mole

Molar mass of aluminium = 27.0 g/mol

Putting values in above equation, we get:

Hence, the mass of aluminium metal that must be added is 27.0 grams

the answer is: they rebelled against saddam hussein’s rule.

kurds opposed saddam rule and wanted independence. kurds in the north and shiites in the south revolt against hussein.

for example, the halabja attack in 1988 conducted against the kurdish people by the iraqi regime under saddam hussein, where between 4000 people are killed and around 9000 are injured.