Vinegar contains 5.0g of acetic acid, ch3cooh, in 100.0 ml of solution what is the molarity of acetic acid in vinegar

0.83 M

Explanation: Molarity is moles of solute per liter of solution.

Mass of solute(acetic acid) is given as 5.0 g and the volume of solution is 100.0 mL.

We need to convert the grams of acetic acid to moles and for this we divide the grams by molar mass.

Formula of acetic acid is . Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)  

= 24.02 + 4.04 + 32

= 60.06 grams per mol

moles of acetic acid = 5.0/60.06 = 0.083 moles

Convert mL to L.

we know that, 1 L = 1000 mL

So, to convert mL to L we divide by 1000.

= 0.1000 L

molarity of the solution =

= 0.83M

So, the molarity of acetic acid in vinegar is 0.83 M.

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year