Determine if the bond between each pairs of atoms would be pure covalent, polar covalent, or ionic. n and se

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

                Less than 0.4 then it is Non Polar Covalent Bond

                Between 0.4 and 1.7 then it is Polar Covalent Bond

                Greater than 1.7 then it is Ionic

For N and Se,

                    E.N of Nitrogen         =   3.04

                    E.N of Selenium        =   2.55

                    E.N Difference             0.49          (Weakly Polar Covalent)

As you have not provided remaining pairs, so if you have any of them, follow the method as mentioned above.