If 72.0 grams of aluminum are reacted with 252 grams of hydrochloric acid, how many grams of aluminum chloride are produced by this reaction? 2al(s) + 6hcl(aq) → 2alcl3(aq) + 3h2(g)

Answer : The mass of produced will be, 46.935 grams.

Explanation : Given,

Mass of = 9.5 g

Mass of = 130 g

Molar mass of = 26.98 g/mole

Molar mass of = 36.5 g/mole

Molar mass of = 133.34 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 6 mole of

So, 0.352 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of .

As, 2 moles of react to give 2 moles of

So, 0.352 moles of react to give 0.352 moles of

Now we have to calculate the mass of .

Therefore, the mass of produced will be, 46.935 grams.

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