The heat of vaporization of water is 40.66 kj/mol. how much heat is absorbed when 2.46 g of water boils at atmospheric pressure?

Change mass to moles. There are 18 grams in one mole of water.

2.45g / 18g = .14 moles of water

The heat absorbed is 40.66 kJ for each mol so

40.66 x .14 = 5.5 kJ 

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