What is the molarity of 12.5 g ch3oh in 50.0 ml of solution?

Data Given:
                   Mass  =  12.5 g

                   M.mass of Methanol  =  32.04 g/mol

                   Volume  =  50 ml ÷ 1000 =  0.05 L
Solution:

First of all calculate moles of Methanol,
  
                           Moles  =  Mass / M.mass

                           Moles  =  12.5 g / 32.04 g.mol⁻¹

                           Moles  =  0.39 mol

As we know Molarity is given as,

                          Molarity  =  Moles / Volume of Solution

Putting Values,

                          Molarity  =  0.39 mol ÷ 0.05 L

                          Molarity  =  7.80 mol.L⁻¹

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