4.5 moles of sodium sulfate contain how many atoms of sulfur

Chemical Formula of Sodium Sulfate is Na₂SO₄.

As we know, 1 mole of any substance contains 6.022 × 10²³ particles. So, 1 mole of Na₂SO₄ also contains 6.022 × 10²³ formula units of Na₂SO₄.
Also,
                     1 mole of Na₂SO₄ contains  =  6.022 × 10²³ Atoms of S
So,
            4.5 moles of Na₂SO₄ will contain  =  X atoms of S

Solving for X,
                                X  =  (4.5 moles × 6.022 × 10²³ Atoms) ÷ 1 mole

                                X  =  2.70 × 10²⁴ Atoms of S
Result:
            4.5 Moles of Na₂SO₄ contains 2.70 × 10²⁴ Atoms of Sulfur.

Ais the correct answer

Spontaneity tell us the direction of the reaction, but not how fast it goes. gibbs free energy brings together enthalpy, entropy and temperature in one easy formula. g = h - ts. and, finally the sign of delta g is always negative for a spontaneous reaction.