How many electrons in an atom can share the quantum numbers n = 2, l = 1? 1 3 6 10

Answer : The number of electrons held in n = 2, l = 1 are, 6 electrons

Explanation :

There are 4 quantum numbers :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as . The value of this quantum number ranges from . When l = 2, the value of will be -2, -1, 0, +1, +2.

Spin Quantum number : It describes the direction of electron spin. This is represented as The value of this is for upward spin and for downward spin.

As we are given that,

(For each sub-shell)

From this we conclude that, there are 3 orbitals and each orbital contains 2 electrons. So, the number of electrons held in an atom are, electrons.

Hence, the number of electrons held in n = 2, l = 1 are, 6 electrons

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.