How many moles of methane were in the erlenmeyer flask?

Since the question is incomplete, I can help you with a detailed explanation on how to calculate the number of moles of mehate in an erlenmeyer flask.

There are two possible scenaries for this question.

1) Scenary I. Known mass.

Whether you are given the mass or other information that permits to calculate the mass of methane, you can work with the molecular formula to calculate the number of moles, in this way:

i) Methane chemical formula: CH₄

ii) Molar masss: sum the mass of each element in the formula, using the atomic mass and number of atoms of each.

Molar mass = 12.011 g/mol + 4× 1.008 g/ mol = 16.043 g/mol

iii) Number of moles

Formula: number of moles = mass in grams / molar mass = mass in grams / 16.043 g/mol.

That is it. Use the last formula to calculate the number of moles of methane.

2) Scenary 2. P, T,and V known.

You do not know the mass but the conditions: temperature (T), volume (V), and pressure (P).

In this case you use the ideal gas equation:

PV = nRT, from which you clear for the number of moles (n):

n = PV/(RT).

Plug in the data of P, V and T in coherent unit system.

R is the universal law of gases, which you must also use with the appropiate units, depending on the units of P, V, and T used.

For example, R = 0.0821 atm×liter / (K×mol); and R = 8.314 KPa×liter/(mol×K).

i need mutiple choices

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72