Determine if the bond between each pair of atoms is pure covalent, polar covalent, or ionic. drag the appropriate items to their respective bins. br-br n-o p-h k-o

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

                Less than 0.4 then it is Non Polar Pure Covalent

                Between 0.4 and 1.7 then it is Polar Covalent 

                Greater than 1.7 then it is Ionic

For Br and Br,

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                    E.N Difference             0.00         (Non Polar/Pure Covalent)

For N and O,

                    E.N of Oxygen      =   3.44

                    E.N of Nitrogen     =   3.04

                    E.N Difference             0.40           (Non Polar/Pure Covalent)

For P and H,

                    E.N of Hydrogen       =   2.20

                    E.N of Phosphorous  =   2.19

                    E.N Difference                  0.01          (Non Polar/Pure Covalent)

For K and O,

                    E.N of Oxygen          =   3.44

                    E.N of Potassium      =   0.82

                    E.N Difference                2.62              (Ionic)

the answer is 75.0%.